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What is the temperature required in presence of molybdenum and iron for nitrogen to combine with hydrogen?

(a) 123 Kelvin

(b) 273 Kelvin

(c) 673 Kelvin

(d) 473 Kelvin

I had been asked this question in exam.

Question is from Properties of Dihydrogen topic in division Hydrogen of Chemistry – Class 11

1 Answer

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Right answer is (c) 673 Kelvin

The explanation: At 673 Kelvin and 200 atmospheric pressure, one mole of nitrogen combines with three moles of hydrogen in presence of iron and molybdenum in order to form 2 moles of ammonia and the enthalpy change is 92.6 KJ per Mol, the enthalpy here change is negative.

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