The correct answer is (b) 96.4 kg
Explanation: Let us consider 100 kg sample or urea. This is said to contain 45kg N2.
Now, 60kg urea contains 28 kg N2. (Since, Mw of urea = 14 + 2 + 12 + 16 + 14 + 2 = 60kg/kmole)
Then, 1kg urea contains \(\frac{28}{60}\)kg N2.
Using unitary method, x kg urea will contain 45 kg N2.
Solving for x –
x= 45 x \(\frac{60}{28}\) = 96.4 kg.