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What is the Van’t Hoff Factor for 1 mole of BaCl2, assuming 100% dissociation?

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in Chemistry – Class 12 by (188k points)
What is the Van’t Hoff Factor for 1 mole of BaCl2, assuming 100% dissociation?

(a) 0.33

(b) 1

(c) 3

(d) 2

I had been asked this question in an internship interview.

This interesting question is from Abnormal Molar Masses topic in section Solutions of Chemistry – Class 12

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Right answer is (c) 3

Best explanation: Van’t Hoff Factor can also be written as the ratio between the total number of moles of particles after association / dissociation and the total number of moles of particles before association / dissociation. Since BaCl2 completely dissociates(into one Ba^2+ and two Cl^– ions), the total number of moles after dissociation is equal to 3. Therefore, the Van’t Hoff Factor for BaCl2 is 3.

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