The correct answer is (b) 0.160
The best I can explain: Given,
P^0water =23.8 mm Hg
Pwater= 2.0 cm Hg = 20.0 mm Hg (after addition of solute)
From the law of relative lowering of vapor pressure, ∆p1 = X2 x p^01 (where X2 is the mole fraction of solute)
On rearranging, Δp1/p^01 =X2
Δp1 = 23.8 – 20.0 = 3.8 mm Hg
X2 = 3.8/23.8 = 0.160.