Correct option is (b) Cl2 > Br2 > F2 > I2
Easiest explanation: Enthalpy of dissociation decreases as the bond distance increases from F2 to I2 due to a corresponding increase in the size of the atom as we move down the group from F to I. The F-F bond dissociation enthalpy is, however, smaller than that of Cl-Cl and even smaller than that of Br-Br. This is due to the reason that F atom is very small and hence the electron-electron repulsions between the lone pairs of electrons are very large.