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How many geometrical isomers are possible in [Al(C2o4)3]^3-?

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in Chemistry – Class 12 by (188k points)
How many geometrical isomers are possible in [Al(C2o4)3]^3-?

(a) 0

(b) 2

(c) 3

(d) 4

I got this question in final exam.

Asked question is from Isomerism in Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

1 Answer

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Best answer
The correct option is (a) 0

Easiest explanation: The entity shown has a CN=6 as oxalate is a bidentate ligand. The structure of the entity will be same no matter which positions in the geometry each of the oxalate ligands occupy because their relative positions will remain the same in each case.

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