The correct option is (d) +6
Best explanation: In [Co(H2O)(CN)(en)2]^2+, the overall charge is +2 and 0, -1 and 0 on H2O, CN and en groups respectively. If ‘x’ is the oxidation number of Co, then (x + 0 – 1 + 0 = +2), which implies x=+3. Similarly, in [CoBr2(en)2]^+, the charge on Br is -1, so if ‘y’ is the oxidation number of Co, then (y – 2 + 0 = +1), which implies y=+3. Therefore, the sum of the oxidation numbers is 3 + 3 = 6.