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How many monohaloalkane isomers can be formed on the free radical bromination of (CH3)2CHCH2CH3?

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in Chemistry – Class 12 by (188k points)
How many monohaloalkane isomers can be formed on the free radical bromination of (CH3)2CHCH2CH3?

(a) 2

(b) 3

(c) 4

(d) 5

This question was addressed to me in an online quiz.

This intriguing question comes from Methods of Preparation of Haloalkanes topic in chapter Haloalkanes and Haloarenes of Chemistry – Class 12

1 Answer

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Best answer
The correct choice is (c) 4

Easy explanation: There are four different types of hydrogen atoms that can be replaced to give the following four isomers; (CH3)2CHCH2CH2Br, (CH3)2CHCH(Br)CH3, (CH3)2C(Br)CH2CH3 and CH3CH(CH2Br)CH2CH3.

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