When (-)-2-bromooctane reacts with potassium hydroxide over an SN2 mechanism, what will be the product formed?
(a) (-)-octan-1-ol
(b) (+)-octan-1-ol
(c) (-)-octan-2-ol
(d) (+)-octan-2-ol
I had been asked this question during an interview.
This interesting question is from Haloalkanes & Haloarenes in division Haloalkanes and Haloarenes of Chemistry – Class 12