Right answer is (b) Diborane
For explanation I would say: Diborane (B2H6) reacts with alkenes to give trialkyl boranes as a product of successive addition. Firstly, CH3CH2CH2(BH2) is formed which reacts with propene to give (CH3CH2CH2)2BH, which further reacts with propene to finally give (CH3CH2CH2)B, which is tripropyl borane.