Right choice is (b) Propanoic acid and ethanoic acid
The best explanation: Ketones undergo oxidation accompanied by C-C bond cleavage to give a mixture of carboxylic acids having lesser number of carbon atoms than the parent ketone. In case of petan-2-one (which is unsymmetrical), the cleavage occurs such that the CO group stays with the smaller alkyl group (Popoff’s rule). Hence, the bond between C-2 and C-3 will be broken to give a mixture of ethanoic acid and propanoic acid.