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Cyclohexanone on treatment with hydroxylamine gives P, which on treatment with sulphuric acid gives Q. When Q is heated with water at high temperature, R is obtained. Identify R.

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Cyclohexanone on treatment with hydroxylamine gives P, which on treatment with sulphuric acid gives Q. When Q is heated with water at high temperature, R is obtained. Identify R.

(a) Nylon-6

(b) Caprolactam

(c) Amino caproic acid

(d) Nylon-6,6

I have been asked this question during an online interview.

The query is from Types of Polymerisation Reactions in portion Polymers of Chemistry – Class 12

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Right answer is (a) Nylon-6

The explanation is: Nylon-6 is the polymer of caprolactam (Q), which is obtained from the oxidation of cyclohexane to give cyclohexanone(P), followed by treatment with H2SO4. Caprolactam on heating with water gives amino caproic acid which polymerises to nylon-6.

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