Question

Assume that the growth of bacteria follows first order kinetics with a rate constant of 2/s. If the initial population of the bacteria is 2000, then the population of it after 30s will be _____

(a) 2 × 10^29

(b) 4 × 10^29

(c) 2 × 10^30

(d) 8 × 10^29

This question was posed to me in an online interview.

My question is based upon Biological Classification in division Biological Classification of Biology – Class 11

Answer 1

Right answer is (a) 2 × 10^29

To elaborate: n = N×e^kt = N×10^kt/2.303

Where, n = current population

            N = initial population

            k = rate constant

            t = time taken

n = 2000×10^2×30/2.303 = 2×10^29.