What happens when only one argument is supplied to set() function?
(a) All bits are set to 1 in a bitset
(b) Bit corresponding to an argument is set to 1
(c) All alternate bits are set to 1 in a bitset
(d) First bit is set to 1
I got this question during an online interview.
My question is taken from Bitset in chapter Class Hierarchies, Library & Containers of C++