Right choice is (d) irrational number
Explanation: Let’s take one rational number and one irrational number for example.
Consider 3 and \(\sqrt{2}\)
We know that 3 is rational number and \(\sqrt{2}\) is irrational number.
By adding 3 and \(\sqrt{2}\), we get 3+\(\sqrt{2}\)
We know that \(\sqrt{2}\) = 1.414213…
Since the expansion of \(\sqrt{2}\) is non-terminating and non-recurring, expansion of 3+\(\sqrt{2}\) will also be non-terminating and non-recurring. Therefore result of summation will be irrational number.
The same will happen if we subtract \(\sqrt{2}\) from 3.
Hence we can say that Summation or Subtraction of rational number and irrational number is always irrational number.