Correct option is (b) False
The best I can explain: For an expression to be a polynomial, exponent of variable has to be whole number.
\(\frac{1}{\sqrt[2]{x}}\) can be written as x^-1/2. We can see that exponent of x is -1/2 which is not whole number (W = {0, 1, 2, 3…}). Hence, \(\frac{1}{\sqrt[2]{x}}\) is not a polynomial.