Correct option is (d) 3m, 3m + 1
Easiest explanation: Let a be any arbitrary number.
Then, by Euclid’s division lemma,
a = 3q + r where 0 ≤ r ≤ 3
a^2 = (3q + r)^2 = 9q^2 + r^2 + 6qr
When r = 0,
Then, a^2 = 9q^2 + 0^2 + 6q(0)
= 9q^2 = 3(3q^2) = 3m where m = 3q^2
Now, r = 1
a^2 = (3q+r)^2
= 9q^2 + (1)^2 + 6q(1)
= 9q^2 + 1 + 6q
= 3(3q^2 + 2q) + 1 = 3m + 1 where m = 3q^2 + 2q
When r = 2,
a^2 = (3q+r)^2
= 9q^2 + (2)^2 + 6q(2)
= 9q^2 + 12q + 4
= 3(3q^2) + 3(4)q + 3 × 1 + 1
= 3[(3q^2) + (4)q + 1] + 1
= 3m + 1 where m = (3q^2) + (4)q + 1
Hence, square of number n is of the form 3m or 3m + 1