The correct option is (c) 275
For explanation I would say: The AP according to the given data will be 19, 38, 57, …, 95
Here a = 19 and d = 19
Tn = a + (n – 1)d = 95
19 + (n – 1)19 = 95
19 + 19n – 19 = 95
19n = 95
n = 5
We know that, Sn = \(\frac {n}{2}\) (a + l)
Sn = \(\frac {5}{2}\) ((19) + 95)
Sn = 285