Right choice is (d) cot θ + tan θ
The explanation: cosec θ sec θ = \frac {1}{sin \, \theta } \frac {1}{cos \, \theta }
= \frac {1}{sin \, \theta \, cos \, \theta } (cos^2θ + sin^2θ)
= \frac {cos \, \theta }{sin \, \theta } + \frac {sin \, \theta }{cos \, \theta }
= cot θ + tan θ