Right choice is (d) cot θ + tan θ
The explanation: cosec θ sec θ = \(\frac {1}{sin \, \theta } \frac {1}{cos \, \theta } \)
= \(\frac {1}{sin \, \theta \, cos \, \theta } \)(cos^2θ + sin^2θ)
= \(\frac {cos \, \theta }{sin \, \theta } + \frac {sin \, \theta }{cos \, \theta } \)
= cot θ + tan θ