Question

If sin A = \(\frac {3}{5}\), then find tan A.

(a) \(\frac {3}{4}\)

(b) \(\frac {3}{5}\)

(c) \(\frac {5}{3}\)

(d) \(\frac {4}{3}\)

This question was posed to me by my college director while I was bunking the class.

I need to ask this question from Trigonometric Ratios topic in section Trigonometry of Mathematics – Class 10

Answer 1

Right option is (a) \(\frac {3}{4}\)

Easy explanation: Sin A = \(\frac {Opposite \, side}{Hypotenuse} = \frac {3}{5}\)

From Pythagoras theorem, (Hypotenuse)^2 = (Opposite side)^2 + (Adjacent side)^2

5^2 = 3^2 + (Adjacent side)^2

(Adjacent side)^2 = 5^2 – 3^2

Adjacent side = √16 = 4

Tan A = \(\frac {Opposite \, side}{Adjacent \, side} = \frac {3}{4}\)