Right option is (b) False
Explanation: Consider, two triangles ABC and DEF
In ∆ABC,
sin B = \(\frac {AC}{AB} = \frac {10}{20} = \frac {1}{2}\) i.e. B = 30°
Now, in ∆DEF,
sin F = \(\frac {DE}{DF} = \frac {20}{40} = \frac {1}{2}\) i.e. F = 30°
From these examples it is evident that the value of the trigonometric ratios depends on their angle and not on their lengths.