Question

The value of sin 90° + cos 0° + √2 cos 45° is_____

(a) 2

(b) 1

(c) 4

(d) 3

I got this question in an internship interview.

I'd like to ask this question from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

Answer 1

Correct choice is (d) 3

Best explanation: sin 90° + cos 0° + √2 cos 45° = 1 + 1 + √2 (\(\frac {1}{\sqrt {2}}\))

= 1 + 1 + 1

= 3