Question

A pole stands vertically on the floor. From a point, it is 120 meters away from the foot of the pole and the angle of elevation is 45° then find the height of the pole.

(a) 100 meters

(b) 180 meters

(c) 120 meters

(d) 10 meters

I got this question in final exam.

Asked question is from Trigonometry Application topic in division Trigonometry Application of Mathematics – Class 10

Answer 1

Right option is (c) 120 meters

To explain: In the figure, BC is the height of the pole.

In ∆ABC, Tan 45° = \(\frac {BC}{AB}\)

1 = \(\frac {BC}{AB}\)

1 = \(\frac {BC}{120}\)

BC = 120 meters