Question

The area of the sector is _____

(a) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2

(b) \(\frac {x^{\circ }}{360^{\circ }}\) – πr^2

(c) \(\frac {x^{\circ }}{360^{\circ }}\) + πr^3

(d) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^3

This question was posed to me in an internship interview.

The above asked question is from Number of Tangents from a Point on the Circle topic in portion Circles of Mathematics – Class 10

Answer 1

Right answer is (a) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2

Explanation: The area of the sector is \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2

Where x° is the degree measure of the angle at the center and r is the radius of the circle.