Question

What is the probability of getting factors of 3 when a die is rolled?

(a) \(\frac {1}{3}\)

(b) \(\frac {2}{3}\)

(c) \(\frac {1}{6}\)

(d) 0

This question was posed to me in exam.

Question is from Theoretical Approach to Probability topic in chapter Probability of Mathematics – Class 10

Answer 1

Correct option is (a) \(\frac {1}{3}\)

To elaborate: Total number of outcomes are {1, 2, 3, 4, 5, 6} = 6

Factors of 3 in total outcomes are {3, 6} = 2

P(E) = \(\frac {Number \, of \, favorable \, outcomes}{Total \, number \, of \, outcomes}\)

= \(\frac {2}{6}\)

= \(\frac {1}{3}\)