Right answer is (c) n (A ∪ B) = n (A) + n (B) – n (A ∩ B)
For explanation I would say: In the Venn diagram,
n (A ∪ B) = a + b + c
n(A) = a + c, n(B) = b + c and n (A ∩ B) = c
n (A) + n (B) – n (A ∩ B) = (a + c) + (b + c)-c = a + b + c.
Hence, n (A ∪ B) = n (A) + n (B) – n (A ∩ B).