The correct choice is (b) (-∞, -√7] ∪ [√7, ∞)
Best explanation: We have, log1/2 x^2 ≥ log1/2 (x + 2)
=> x^2 ≤ x + 2
=> -1 ≤ x ≤ 2
And, 49x^2 – 4a^4 ≤ 0 i.e. x^2 ≤ 4a^4 / 49
=> -2a^2/7 ≤ a ≤ 2a^2/7
From the above equations,
-2a^2/7 ≤ -1 and 2 ≤ 2a^2/7
i.e. a^2 € 7/2 and a^2 ≥ 7
=> a € (-∞, -√7] ∪ [√7, ∞)
So, S = (-∞, -√7] ∪ [√7, ∞)