Question

Find the distance between two points (5, 6, 7) and (2, 6, 3).

(a) 3 units

(b) 0 units

(c) 4 units

(d) 5 units

The question was posed to me during an online interview.

My query is from Three Dimensional Geometry topic in portion Three Dimensional Geometry of Mathematics – Class 11

Answer 1

The correct answer is (d) 5 units

To explain: We know, distance between two points (x1, y1, z1) and (x2, y2, z2) is \(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}\).

So, distance between two points (5, 6, 7) and (2, 6, 3) will be \(\sqrt{(5-2)^2+(6-6)^2+(7-3)^2}\) = \(\sqrt{(3)^2+(4)^2}\) = 5 units.