Question

If vertex is at (1, 2) and focus (2, 0) then find the equation of the parabola.

(a) y^2-8x+4y+12=0

(b) y^2-8x-4y-12=0

(c) y^2-8x-4y+12=0

(d) y^2+8x+4y+12=0

The question was asked in final exam.

My enquiry is from Conic Sections in chapter Conic Sections of Mathematics – Class 11

Answer 1

The correct option is (c) y^2-8x-4y+12=0

Easiest explanation: Since vertex is at (1, 2) and focus (2, 0) so parabola equation will be

(y-2)^2=4*2(x-1)

y^2-8x-4y+12=0.