Correct choice is (c) 2
For explanation I would say: The limit can be written as, \lim\limits_{x \rightarrow 0}\frac{32x^2}{sin^24x}
= 2 x \lim\limits_{x \rightarrow 0}\frac{4x}{sin 4x} x \lim\limits_{x \rightarrow 0}\frac{4x}{sin 4x}
= 2 x 1 x 1
= 2