Question

What is the value of the limit \(\lim\limits_{x \rightarrow 4}\frac{x^2-4-3x}{x-3}\)?

(a) 0

(b) 4

(c) 1

(d) Limit does not exist

The question was posed to me by my college director while I was bunking the class.

The above asked question is from Limits topic in portion Limits and Derivatives of Mathematics – Class 11

Answer 1

The correct choice is (a) 0

To elaborate: \(\lim\limits_{x \rightarrow 4}\frac{x^2-4-3x}{x-3}\)

= \(\frac{4^2-4-3(4)}{4-3}\)

= \(\frac{0}{1}\)

= 0.