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Line perpendicular to line joining (1, 3) and (4, 5) and pass through (2, 4) has equation ____________

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in Mathematics - Class 11 by (789k points)
Line perpendicular to line joining (1, 3) and (4, 5) and pass through (2, 4) has equation ____________

(a) 3x+2y-14=0

(b) 3x-2y-14=0

(c) 2x-3y-14=0

(d) 2x+3y-14=0

The question was posed to me during an online interview.

The query is from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

1 Answer

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Best answer
Correct answer is (a) 3x+2y-14=0

Best explanation: Slope of line joining (1, 3) and (4, 5) is (5-3) / (4-1) = 2/3

So, slope of line perpendicular to it is -3/2.

Line has slope -3/2 and pass through (2, 4)

So, equation is y-4 = (-3/2)(x-2) => 2y-8 = -3x+6 => 3x+2y-14=0.

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