Question

^nCn = ________________

(a) n!

(b) 1

(c) \(\frac{1}{(n)!}\)

(d) (n-1)!

The question was asked by my school teacher while I was bunking the class.

This interesting question is from Combinations in section Permutations and Combinations of Mathematics – Class 11

Answer 1

Correct answer is (b) 1

The best I can explain: We know, ^nCr = \(\frac{n!}{(n-r)! r!}\).

^nCn = \(\frac{n!}{(n-n)! n!} = \frac{n!}{(0)! n!}\) = 1/1 = 1.