Right answer is (b) 27 sq. units
To explain I would say: We know, area of triangle joining vertices (x1, y1), (x2, y2) and (x3, y3) is (1/2)* determinant \(\begin{pmatrix}-4 & -4 &1 \\-3& 2 & 1\\ 3& -16 & 1\end{pmatrix}\) is \(\frac{1}{2}\){(-4)(2+16) – (-4)(-3-3) + (1)(48-6)} = \(\frac{1}{2}\)|(-72)+(-24)+42| = 27 square units.