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If 4 bulbs are there each of which can be defective or non-defective then what is the total number of possible outcomes?

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in Mathematics - Class 11 by (789k points)
If 4 bulbs are there each of which can be defective or non-defective then what is the total number of possible outcomes?

(a) 8

(b) 16

(c) 4

(d) 2

This question was posed to me by my college director while I was bunking the class.

This is a very interesting question from Probability in portion Probability of Mathematics – Class 11

1 Answer

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Best answer
The correct choice is (b) 16

To elaborate: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 2^4 = 16.

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