Correct option is (b) [0, π/4) and (5π/4, 2π]
To explain I would say: f(x) = sinx+cosx.
f’(x) = cosx – sinx. Now f’(x) = 0 gives sinx = cosx which gives that x= π/4, 5π/4 as 0 ≤ x ≤ 2π.
The points x = π/4 and x = 5π/4 divide the interval [0, 2π] into three disjoint intervals which are
[0, π/4), (π/4, 5π/4) and (5π/4, 2π].
Therefore on checking the values we get f is increasing in [0, π/4) and (5π/4, 2π].