Question

Evaluate \(\begin{vmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{vmatrix}\).

(a) 6-3\(\sqrt{2}\)

(b) 6-\(\sqrt{2}\)

(c) 6+3\(\sqrt{2}\)

(d) 6+\(\sqrt{2}\)

This question was addressed to me in an online quiz.

This question is from Determinant in portion Determinants of Mathematics – Class 12

Answer 1

Correct answer is (d) 6+\(\sqrt{2}\)

To explain: ∆=\(\begin{vmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{vmatrix}\)

∆=(\(\sqrt{3}\)×2\(\sqrt{3}\))+\(\sqrt{2}\)

∆=6+\(\sqrt{2}\).