Correct option is (c) 8.01875
The explanation: Let y=\(\sqrt{x}\). Let x=64 and Δx=0.3
Then, Δy=\(\sqrt{x+Δx}-\sqrt{x}\)
Δy=\(\sqrt{64.3}-\sqrt{64}\)
\(\sqrt{64.3}\)=Δy+8
dy is approximately equal to Δy is equal to:
dy=\(\frac{dy}{dx}\)Δx
dy=\(\frac{1}{2\sqrt{x}}\).Δx
dy=\(\frac{1}{2\sqrt{64}}\) (0.3)
dy=0.3/16=0.01875
∴ The approximate value of \(\sqrt{64.3}\) is 8+0.01875=8.01875