Right choice is (d) 4\(\hat{i}\)+\(\hat{j}\)
To elaborate: Given that, \(\vec{a}+\vec{b}\)+\(\vec{c}\)=8\(\hat{i}\)+2\(\hat{j}\) -(1)
Given: \(\vec{a}\)=\(\hat{i}\)-6\(\hat{j}\) and \(\vec{c}\)=3\(\hat{i}\)+7\(\hat{j}\)
Substituting the values of \(\vec{a}\) and \(\vec{b}\) in equation (1), we get
\(\vec{a}+\vec{b}\)+\(\vec{c}\)=8\(\hat{i}\)+2\(\hat{j}\)
(\(\hat{i}\)-6\(\hat{j}\))+\(\vec{b}\)+(3\(\hat{i}\)+7\(\hat{j}\))=8\(\hat{i}\)+2\(\hat{j}\)
∴\(\vec{c}\)=(8\(\hat{i}\)+2\(\hat{j}\))-(\(\hat{i}\)-6\(\hat{j}\))-(3\(\hat{i}\)+7\(\hat{j}\))
=(8-1-3) \(\hat{i}\)+(2+6-7) \(\hat{j}\)
=4\(\hat{i}\)+\(\hat{j}\)