Correct choice is (b) False
The best explanation: The given statement is false.
Given differential equation: \(\frac{d^2 y}{dx^2}\)-3 \(\frac{dy}{dx}\)=0 –(1)
Consider the function y=3 cosx
Differentiating w.r.t x, we get
\(\frac{dy}{dx}\)=-3 sinx
Differentiating again w.r.t x, we get
\(\frac{d^2 y}{dx^2}\)=-3 cosx
Substituting the values of \(\frac{dy}{dx}\) and \(\frac{d^2 y}{dx^2}\) in equation (1), we get
\(\frac{d^2 y}{dx^2}\)-3 \(\frac{dy}{dx}\)=-3 cosx-3(-3 sinx)
=9 sinx-3 cosx≠0.
Hence, y=3 cosx, is not a solution of the equation \(\frac{d^2 y}{dx^2}\)-3 \(\frac{dy}{dx}\)=0.