Question

A dice is thrown twice, what is the probability of getting two 3’s?

(a) \(\frac {1}{66}\)

(b) \(\frac {1}{16}\)

(c) \(\frac {1}{36}\)

(d) \(\frac {1}{36}\)

The question was posed to me in final exam.

I'd like to ask this question from Probability topic in portion Probability of Mathematics – Class 12

Answer 1

The correct option is (d) \(\frac {1}{36}\)

To elaborate: Probability of getting 3 in the first throw = \(\frac {1}{6}\)

Probability of getting of 3 in the second throw = \(\frac {1}{6}\)

Total probability = \(\frac {1}{6} \times \frac {1}{6} = \frac {1}{36}\)