Right choice is (c) 2
Easiest explanation: We have, x^4 –8x^3 + 22x^2 –24x + 8 ……….(1)
Differentiating both sides of (1) with respect to x, we get,
f’(x) = 4x^3 – 24x^2 + 44x – 24 and f”(x) = 12x^2 – 48x + 44 ……….(2)
At an extremum of f(x), we have f’(x) = 0
Or 4x^3 – 24x^2 + 44x – 24 = 0
Or x^2(x – 1) – 5x(x – 1) + 6(x – 1) = 0
Or (x – 1)(x^2 – 5x + 6) = 0
Or (x – 1)(x – 2)(x – 3) = 0
So, x = 1, 2, 3
Now, f”(x) = 12x^2 – 48x + 44
f”(1) = 8 > 0
f”(2) = -4 < 0
f”(3) = 8 < 0
So, f(x) has maximum at x = 2.