Question

What will be the shape of Rankine oval when U*y+ ((-u/2*pi*r) = 0?

(a) open curve

(b) closed body profile

(c) straight line

(d) point

The question was posed to me by my school teacher while I was bunking the class.

My question comes from Nonlifting Flow over Cylinder in division Inviscid & Incompressible Flow of Aerodynamics

Answer 1

Right answer is (b) closed body profile

The best I can explain: The shape of the Rankine oval of equal axes can be given by substituting the stream function as zero in the equation Ψ = U*y + ((-u/2*pi*r)*sin θ. When U*y+ ((-u/2*pi*r) =0, a closed profile body is a circular cylinder of radius R with the centre on the doublet.