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Prandtl relation can also be expressed in terms of characteristic Mach number as 1=M\(_1^*\)M\(_2^*\).

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Prandtl relation can also be expressed in terms of characteristic Mach number as 1=M\(_1^*\)M\(_2^*\).

(a) True

(b) False

I got this question in an internship interview.

My doubt is from Flow Compressible topic in chapter Normal Shock Waves of Aerodynamics

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Best answer
Correct option is (a) True

To explain: The Prandtl relation is given as a^*2=u1u2 while the characteristic Mach number is given as M*=\(\frac {u}{a^{*}}\). So, putting this into the Prandtl relation we get the equation 1=M\(_1^*\)M\(_2^*\) where M\(_1^*\) and M\(_2^*\) are the characteristic Mach number upstream and downstream of the normal shock.

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