Right choice is (d) 1.115
Explanation: Given, P01 = 1 atm, Pe = 0.3143 atm
To calculate – \(\frac {A_e}{A^*}\)
Stagnation pressures remain same P01 = P0e
\(\frac {P_{0e}}{P_e} = \frac {1}{0.3143}\) = 3.182
For \(\frac {P_{0e}}{P_e}\) = 3.182 we get Me = 1.4 (Using gas table)
For Me = 1.4, we get \(\frac {A_e}{A^*}\) = 1.115 (Using gas table)