Right choice is (b) Decreases
To explain: The relation between the shear stress and the viscous shear layer is given by:
τ = μ(\(\frac {u_e}{D}\))
Where, ue is the velocity at y = D that is at the upper plate.
τ is the shear stress
D is the thickness of the vicsous shear layer/distance between the two parallel plates
As peer the formula, then the thickness of the viscous shear layer increases, the shear stress decreases provided the other properties remain the same.