Question

What is the value of equilibrium constant based on concentrations if the forward and reverse rate constant of a non – equilibrium reaction are 1.85 × 10^-4 and 2.34 × 10^-5?

(a) 6.45

(b) 7.91

(c) 8.43

(d) 2.31

I got this question during an interview.

My doubt is from Chemical Equilibrium in High Temperature Air in section Properties of High Temperature Gases of Aerodynamics

Answer 1

The correct answer is (b) 7.91

To elaborate: Given, kf = 1.85 × 10^-4 , kb  = 2.34 × 10^-5

The equilibrium constant based on concentrations for non – equilibrium is same as derived for the equilibrium condition since it relates the forward and reverse rate constants. It is given by:

kc = \(\frac {k_f}{k_b}\)

Substituting the values, we get,

kc = \(\frac {1.85 × 10^{- 4}}{2.34 × 10^{- 5}}\) = 7.91