The correct answer is (a) 1.076
The explanation: Given,
Design take-off gross weight, W0 = 5600lb = 2539.6825kg
Crew load = 175kg
Payload weight = 1400kg, fuel weight = 500kg
Now the design take – off gross weight is given by,
W0 = Wcrew + Wpayload + Wfuel + Wempty
2539.682 = 175+ 1400 + 500 + Wempty
So, Wempty = 464.682kg
Fuel weight fraction = Wfuel / W0
Empty weight fraction = Wempty / W0
Now fuel to empty weight fraction = Wfuel / Wempty = 500/464.682 = 1.076.