Right answer is (a) 5.832m/s
The best explanation: Given wing loading W/S = 50, maximum CL = 2.4, density ρ = 1.225
Now, stall speed of aircraft is given by,
Vstall = \(\sqrt{2*(\frac{W}{S})(\rho*CL)} = \sqrt{2*(50)/(1.225*2.4)} = \sqrt{34.01}\) = 5.832m/s.