Correct choice is (a) P\(\sqrt{\sigma}\)=YVe^3+\(\frac{ZW^2}{V_e}\)
The explanation is: The correct relation between EAS and drag power is P\(\sqrt{\sigma}\)=YVe^3+\(\frac{ZW^2}{V_e}\) where Y is a constant, Ve is velocity, W is weight, Z is constant and D is total drag and P is power.